2=(x/12)+3x

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Solution for 2=(x/12)+3x equation: 



2=(x/12)+3x

We move all terms to the left:

2-((x/12)+3x)=0



Domain of the equation: 12)+3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+x/12)+3x)+2=0

We multiply all the terms by the denominator


-((+x+2*12)+3x)=0



We calculate terms in parentheses: -((+x+2*12)+3x), so:

(+x+2*12)+3x

We add all the numbers together, and all the variables

(x+24)+3x

We add all the numbers together, and all the variables

3x+(x+24)

We get rid of parentheses

3x+x+24

We add all the numbers together, and all the variables

4x+24

Back to the equation:

-(4x+24)



We get rid of parentheses

-4x-24=0

We move all terms containing x to the left, all other terms to the right

-4x=24

x=24/-4

x=-6

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