(3a+43)=(2a+36)

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Solution for (3a+43)=(2a+36) equation: 



(3a+43)=(2a+36)

We move all terms to the left:

(3a+43)-((2a+36))=0

We get rid of parentheses

3a-((2a+36))+43=0



We calculate terms in parentheses: -((2a+36)), so:

(2a+36)

We get rid of parentheses

2a+36

Back to the equation:

-(2a+36)



We get rid of parentheses

3a-2a-36+43=0

We add all the numbers together, and all the variables

a+7=0

We move all terms containing a to the left, all other terms to the right

a=-7

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