1/2(-10x+4)=-4(-3+2x)+8

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Solution for 1/2(-10x+4)=-4(-3+2x)+8 equation: 



1/2(-10x+4)=-4(-3+2x)+8

We move all terms to the left:

1/2(-10x+4)-(-4(-3+2x)+8)=0



Domain of the equation: 2(-10x+4)!=0

x∈R



We add all the numbers together, and all the variables

1/2(-10x+4)-(-4(2x-3)+8)=0

We multiply all the terms by the denominator


-((-4(2x-3)+8))*2(-10x+4)+1=0



We calculate terms in parentheses: -((-4(2x-3)+8))*2(-10x+4), so:

(-4(2x-3)+8))*2(-10x+4

We add all the numbers together, and all the variables

-10x+(-4(2x-3)+8))*2(+4

Back to the equation:

-(-10x+(-4(2x-3)+8))*2(+4)



We add all the numbers together, and all the variables

-(-10x+(-4(2x-3)+8))*24+1=0

We move all terms containing x to the left, all other terms to the right

-(-10x+(-4(2x-3)+8))*24=-1

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