(35+32)+58=35+(32+q)

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Solution for (35+32)+58=35+(32+q) equation: 



(35+32)+58=35+(32+q)

We move all terms to the left:

(35+32)+58-(35+(32+q))=0

We add all the numbers together, and all the variables

-(35+(q+32))+58+67=0

We add all the numbers together, and all the variables

-(35+(q+32))+125=0



We calculate terms in parentheses: -(35+(q+32)), so:

35+(q+32)

determiningTheFunctionDomain
(q+32)+35

We get rid of parentheses

q+32+35

We add all the numbers together, and all the variables

q+67

Back to the equation:

-(q+67)



We get rid of parentheses

-q-67+125=0

We add all the numbers together, and all the variables

-1q+58=0

We move all terms containing q to the left, all other terms to the right

-q=-58

q=-58/-1

q=+58

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