-3(C-4)+Z=4c-12

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Solution for -3(C-4)+Z=4c-12 equation: 



-3(-4)+=4C-12

We move all terms to the left:

-3(-4)+-(4C-12)=0

We add all the numbers together, and all the variables

-(4C-12)=0

We get rid of parentheses

-4C+12=0

We move all terms containing C to the left, all other terms to the right

-4C=-12

C=-12/-4

C=+3

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