(33b-2)-8(4b+2)=-7

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Solution for (33b-2)-8(4b+2)=-7 equation: 



(33b-2)-8(4b+2)=-7

We move all terms to the left:

(33b-2)-8(4b+2)-(-7)=0

We add all the numbers together, and all the variables

(33b-2)-8(4b+2)+7=0

We multiply parentheses

(33b-2)-32b-16+7=0

We get rid of parentheses

33b-32b-2-16+7=0

We add all the numbers together, and all the variables

b-11=0

We move all terms containing b to the left, all other terms to the right

b=11

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