(32-x)(190-5x)=0

Solution for (32-x)(190-5x)=0 equation:

(32-x)(190-5x)=0

We add all the numbers together, and all the variables

(-1x+32)(-5x+190)=0

We multiply parentheses ..

(+5x^2-190x-160x+6080)=0

We get rid of parentheses

5x^2-190x-160x+6080=0

We add all the numbers together, and all the variables

5x^2-350x+6080=0

a = 5; b = -350; c = +6080;
Δ = b2-4ac
Δ = -3502-4·5·6080
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-350)-30}{2*5}=\frac{320}{10}
=32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-350)+30}{2*5}=\frac{380}{10}
=38
$