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(2x+10)(4x+1)=360
We move all terms to the left:
(2x+10)(4x+1)-(360)=0
We multiply parentheses ..
(+8x^2+2x+40x+10)-360=0
We get rid of parentheses
8x^2+2x+40x+10-360=0
We add all the numbers together, and all the variables
8x^2+42x-350=0
a = 8; b = 42; c = -350;
Δ = b2-4ac
Δ = 422-4·8·(-350)
Δ = 12964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12964}=\sqrt{4*3241}=\sqrt{4}*\sqrt{3241}=2\sqrt{3241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-2\sqrt{3241}}{2*8}=\frac{-42-2\sqrt{3241}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+2\sqrt{3241}}{2*8}=\frac{-42+2\sqrt{3241}}{16} $
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