(32-2x)(25-2x)=700

Solution for (32-2x)(25-2x)=700 equation:

(32-2x)(25-2x)=700

We move all terms to the left:

(32-2x)(25-2x)-(700)=0

We add all the numbers together, and all the variables

(-2x+32)(-2x+25)-700=0

We multiply parentheses ..

(+4x^2-50x-64x+800)-700=0

We get rid of parentheses

4x^2-50x-64x+800-700=0

We add all the numbers together, and all the variables

4x^2-114x+100=0

a = 4; b = -114; c = +100;
Δ = b2-4ac
Δ = -1142-4·4·100
Δ = 11396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11396}=\sqrt{4*2849}=\sqrt{4}*\sqrt{2849}=2\sqrt{2849}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-114)-2\sqrt{2849}}{2*4}=\frac{114-2\sqrt{2849}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-114)+2\sqrt{2849}}{2*4}=\frac{114+2\sqrt{2849}}{8}
$