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(300-100x)(x-2)=0
We add all the numbers together, and all the variables
(-100x+300)(x-2)=0
We multiply parentheses ..
(-100x^2+200x+300x-600)=0
We get rid of parentheses
-100x^2+200x+300x-600=0
We add all the numbers together, and all the variables
-100x^2+500x-600=0
a = -100; b = 500; c = -600;
Δ = b2-4ac
Δ = 5002-4·(-100)·(-600)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(500)-100}{2*-100}=\frac{-600}{-200} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(500)+100}{2*-100}=\frac{-400}{-200} =+2 $
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