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(3/80)*x+325=1000-0.3x
We move all terms to the left:
(3/80)*x+325-(1000-0.3x)=0
Domain of the equation: 80)*x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/80)*x-(-0.3x+1000)+325=0
We multiply parentheses
3x^2-(-0.3x+1000)+325=0
We get rid of parentheses
3x^2+0.3x-1000+325=0
We add all the numbers together, and all the variables
3x^2+0.3x-675=0
a = 3; b = 0.3; c = -675;
Δ = b2-4ac
Δ = 0.32-4·3·(-675)
Δ = 8100.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3)-\sqrt{8100.09}}{2*3}=\frac{-0.3-\sqrt{8100.09}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3)+\sqrt{8100.09}}{2*3}=\frac{-0.3+\sqrt{8100.09}}{6} $
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