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42=16+2/5b
We move all terms to the left:
42-(16+2/5b)=0
Domain of the equation: 5b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(2/5b+16)+42=0
We get rid of parentheses
-2/5b-16+42=0
We multiply all the terms by the denominator
-16*5b+42*5b-2=0
Wy multiply elements
-80b+210b-2=0
We add all the numbers together, and all the variables
130b-2=0
We move all terms containing b to the left, all other terms to the right
130b=2
b=2/130
b=1/65
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