(3/8)x+11/7=2

Solution for (3/8)x+11/7=2 equation:

(3/8)x+11/7=2

We move all terms to the left:

(3/8)x+11/7-(2)=0


Domain of the equation: 8)x!=0

x!=0/1

x!=0

x∈R


determiningTheFunctionDomain
(3/8)x-2+11/7=0

We add all the numbers together, and all the variables

(+3/8)x-2+11/7=0

We multiply parentheses

3x^2-2+11/7=0

We multiply all the terms by the denominator


3x^2*7+11-2*7=0

We add all the numbers together, and all the variables

3x^2*7-3=0

Wy multiply elements

21x^2-3=0

a = 21; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·21·(-3)
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{7}}{2*21}=\frac{0-6\sqrt{7}}{42}
=-\frac{6\sqrt{7}}{42}
=-\frac{\sqrt{7}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{7}}{2*21}=\frac{0+6\sqrt{7}}{42}
=\frac{6\sqrt{7}}{42}
=\frac{\sqrt{7}}{7}
$