2(3x+2)-7=8x-12(x+3)

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Solution for 2(3x+2)-7=8x-12(x+3) equation: 



2(3x+2)-7=8x-12(x+3)

We move all terms to the left:

2(3x+2)-7-(8x-12(x+3))=0

We multiply parentheses

6x-(8x-12(x+3))+4-7=0



We calculate terms in parentheses: -(8x-12(x+3)), so:

8x-12(x+3)

We multiply parentheses

8x-12x-36

We add all the numbers together, and all the variables

-4x-36

Back to the equation:

-(-4x-36)



We add all the numbers together, and all the variables

6x-(-4x-36)-3=0

We get rid of parentheses

6x+4x+36-3=0

We add all the numbers together, and all the variables

10x+33=0

We move all terms containing x to the left, all other terms to the right

10x=-33

x=-33/10

x=-3+3/10

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