(3/5)a-(1/3)=(-10/3)

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Solution for (3/5)a-(1/3)=(-10/3) equation: 



(3/5)a-(1/3)=(-10/3)

We move all terms to the left:

(3/5)a-(1/3)-((-10/3))=0



Domain of the equation: 5)a!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

(+3/5)a-(+1/3)-((-10/3))=0

We multiply parentheses

3a^2-(+1/3)-((-10/3))=0

We get rid of parentheses

3a^2-1/3-((-10/3))=0

We calculate fractions


3a^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{6}=0$

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