62=3s2

Solution for 62=3s2 equation:

62=3s^2

We move all terms to the left:

62-(3s^2)=0

a = -3; b = 0; c = +62;
Δ = b2-4ac
Δ = 02-4·(-3)·62
Δ = 744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{744}=\sqrt{4*186}=\sqrt{4}*\sqrt{186}=2\sqrt{186}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{186}}{2*-3}=\frac{0-2\sqrt{186}}{-6}
=-\frac{2\sqrt{186}}{-6}
=-\frac{\sqrt{186}}{-3}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{186}}{2*-3}=\frac{0+2\sqrt{186}}{-6}
=\frac{2\sqrt{186}}{-6}
=\frac{\sqrt{186}}{-3}
$