(3/4x)+(7/16)=(4/3x)

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Solution for (3/4x)+(7/16)=(4/3x) equation: 



(3/4x)+(7/16)=(4/3x)

We move all terms to the left:

(3/4x)+(7/16)-((4/3x))=0



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/4x)-((+4/3x))+(+7/16)=0

We get rid of parentheses

3/4x-((+4/3x))+7/16=0

We calculate fractions


(-((+4*4x*16)/192x^2+252x^2/192x^2+144x/192x^2=0

We can not solve this equation

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