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5(y+5)-1=2(y-48)
We move all terms to the left:
5(y+5)-1-(2(y-48))=0
We multiply parentheses
5y-(2(y-48))+25-1=0
We calculate terms in parentheses: -(2(y-48)), so:We add all the numbers together, and all the variables
2(y-48)
We multiply parentheses
2y-96
Back to the equation:
-(2y-96)
5y-(2y-96)+24=0
We get rid of parentheses
5y-2y+96+24=0
We add all the numbers together, and all the variables
3y+120=0
We move all terms containing y to the left, all other terms to the right
3y=-120
y=-120/3
y=-40
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