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(3/4)y-6=2+(1/4)y
We move all terms to the left:
(3/4)y-6-(2+(1/4)y)=0
Domain of the equation: 4)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 4)y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+3/4)y-(2+(+1/4)y)-6=0
We multiply parentheses
3y^2-(2+(+1/4)y)-6=0
We multiply all the terms by the denominator
3y^2*4)y)-(2+(-6*4)y)+1=0
We add all the numbers together, and all the variables
3y^2*4)y)-(2+(-24)y)+1=0
Wy multiply elements
12y^3-24)y)+1=0
We do not support eypression: y^3
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