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(3/4)x-13+3x-17=90
We move all terms to the left:
(3/4)x-13+3x-17-(90)=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/4)x+3x-13-17-90=0
We add all the numbers together, and all the variables
3x+(+3/4)x-120=0
We multiply parentheses
3x^2+3x-120=0
a = 3; b = 3; c = -120;
Δ = b2-4ac
Δ = 32-4·3·(-120)
Δ = 1449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1449}=\sqrt{9*161}=\sqrt{9}*\sqrt{161}=3\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{161}}{2*3}=\frac{-3-3\sqrt{161}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{161}}{2*3}=\frac{-3+3\sqrt{161}}{6} $
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