10-4(x+2)=1/3(6x-9)

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Solution for 10-4(x+2)=1/3(6x-9) equation: 



10-4(x+2)=1/3(6x-9)

We move all terms to the left:

10-4(x+2)-(1/3(6x-9))=0



Domain of the equation: 3(6x-9))!=0

x∈R



We multiply parentheses

-4x-(1/3(6x-9))-8+10=0

We multiply all the terms by the denominator


-4x*3(6x-9))-(1-8*3(6x-9))+10*3(6x-9))=0

We add all the numbers together, and all the variables

-4x*3(6x-9))-(1-8*3(6x-9))+10*3(6x=0

Wy multiply elements

-12x^2(6-72x^2(6=0

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