(3/4)x+(5/8)=(7/12)

Solution for (3/4)x+(5/8)=(7/12) equation:

(3/4)x+(5/8)=(7/12)

We move all terms to the left:

(3/4)x+(5/8)-((7/12))=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)x+(+5/8)-((+7/12))=0

We multiply parentheses

3x^2+(+5/8)-((+7/12))=0

We get rid of parentheses

3x^2+5/8-((+7/12))=0

We calculate fractions


3x^2+()/()+()/()=0

We add all the numbers together, and all the variables

3x^2+2=0

a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation