3g2+51g=0

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Solution for 3g2+51g=0 equation: 



3g^2+51g=0

a = 3; b = 51; c = 0;
Δ = b2-4ac
Δ = 512-4·3·0
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$


$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-51}{2*3}=\frac{-102}{6}
=-17
$


$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+51}{2*3}=\frac{0}{6}
=0
$

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