(3/4)c-(1/3)=5

Solution for (3/4)c-(1/3)=5 equation:

(3/4)c-(1/3)=5

We move all terms to the left:

(3/4)c-(1/3)-(5)=0


Domain of the equation: 4)c!=0

c!=0/1

c!=0

c∈R


determiningTheFunctionDomain
(3/4)c-5-(1/3)=0

We add all the numbers together, and all the variables

(+3/4)c-5-(+1/3)=0

We multiply parentheses

3c^2-5-(+1/3)=0

We get rid of parentheses

3c^2-5-1/3=0

We multiply all the terms by the denominator


3c^2*3-1-5*3=0

We add all the numbers together, and all the variables

3c^2*3-16=0

Wy multiply elements

9c^2-16=0

a = 9; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·9·(-16)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*9}=\frac{-24}{18}
=-1+1/3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*9}=\frac{24}{18}
=1+1/3
$