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(2x-1)+(x+3)=64
We move all terms to the left:
(2x-1)+(x+3)-(64)=0
We get rid of parentheses
2x+x-1+3-64=0
We add all the numbers together, and all the variables
3x-62=0
We move all terms containing x to the left, all other terms to the right
3x=62
x=62/3
x=20+2/3
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