(3/4)b-2=(-7/8)b+3

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Solution for (3/4)b-2=(-7/8)b+3 equation:



(3/4)b-2=(-7/8)b+3
We move all terms to the left:
(3/4)b-2-((-7/8)b+3)=0
Domain of the equation: 4)b!=0
b!=0/1
b!=0
b∈R
Domain of the equation: 8)b+3)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
(+3/4)b-((-7/8)b+3)-2=0
We multiply parentheses
3b^2-((-7/8)b+3)-2=0
We multiply all the terms by the denominator
3b^2*8)b+3)-((-2*8)b+3)-7=0
We add all the numbers together, and all the variables
3b^2*8)b+3)-((-16)b+3)-7=0
Wy multiply elements
24b^3-16)b+3)-7=0
We do not support ebpression: b^3

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