(3/4)b-14=5

Solution for (3/4)b-14=5 equation:

(3/4)b-14=5

We move all terms to the left:

(3/4)b-14-(5)=0


Domain of the equation: 4)b!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

(+3/4)b-14-5=0

We add all the numbers together, and all the variables

(+3/4)b-19=0

We multiply parentheses

3b^2-19=0

a = 3; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·3·(-19)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{57}}{2*3}=\frac{0-2\sqrt{57}}{6}
=-\frac{2\sqrt{57}}{6}
=-\frac{\sqrt{57}}{3}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{57}}{2*3}=\frac{0+2\sqrt{57}}{6}
=\frac{2\sqrt{57}}{6}
=\frac{\sqrt{57}}{3}
$