(3/4)(5x-4)=12

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Solution for (3/4)(5x-4)=12 equation: 



(3/4)(5x-4)=12

We move all terms to the left:

(3/4)(5x-4)-(12)=0



Domain of the equation: 4)(5x-4)!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)(5x-4)-12=0

We multiply parentheses ..

(+15x^2+3/4*-4)-12=0

We multiply all the terms by the denominator


(+15x^2+3-12*4*-4)=0

We get rid of parentheses

15x^2+3-4-12*4*=0

We add all the numbers together, and all the variables

15x^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{30}=0$

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