7=y+3+(y+2)

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Solution for 7=y+3+(y+2) equation: 



7=y+3+(y+2)

We move all terms to the left:

7-(y+3+(y+2))=0



We calculate terms in parentheses: -(y+3+(y+2)), so:

y+3+(y+2)

determiningTheFunctionDomain
y+(y+2)+3

We get rid of parentheses

y+y+2+3

We add all the numbers together, and all the variables

2y+5

Back to the equation:

-(2y+5)



We get rid of parentheses

-2y-5+7=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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