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(3/2x)-(1/x)=(3/5)
We move all terms to the left:
(3/2x)-(1/x)-((3/5))=0
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/2x)-(+1/x)-((+3/5))=0
We get rid of parentheses
3/2x-1/x-((+3/5))=0
We calculate fractions
We do not support expression: x^3
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