(2/3)(x-4)=(1/3)(2x-6

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Solution for (2/3)(x-4)=(1/3)(2x-6 equation: 



(2/3)(x-4)=(1/3)(2x-6

We move all terms to the left:

(2/3)(x-4)-((1/3)(2x-6)=0



Domain of the equation: 3)(x-4)!=0

x∈R





Domain of the equation: 3)(2x-6)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(x-4)-((+1/3)(2x-6)=0

We multiply parentheses ..

(+2x^2+2/3*-4)-((+1/3)(2x-6)=0

We calculate fractions


((+2x^2+2*3)(2x-6))/(-4)*3)(2x-6)+3*)+()/(-4)*3)(2x-6)+3*)=0

We calculate fractions


(((+2x^2+2*3)(2x-6))*(-4)*3)2x/((-4)*3)(2x*(-4)*3)2x-4)*3)2x/((-4)*3)(2x*(-4)*3)2x+(-6)+3*)+()*(=0

We calculate fractions


-4)*3)2x+(-6)+3*)+()*(+((((+2x^2+2*3)(2x-6))*(-4)*3)2x*(()/(((-4)*3)(2x*(-4)*3)2x*(()+(-4)*3)2x*((-4)*3)(2x*(-4)*3)2x)/(((-4)*3)(2x*(-4)*3)2x*(()-4)*3)(2x*(=0

We can not solve this equation

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