(3/2)a+4=14

Solution for (3/2)a+4=14 equation:

(3/2)a+4=14

We move all terms to the left:

(3/2)a+4-(14)=0


Domain of the equation: 2)a!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

(+3/2)a+4-14=0

We add all the numbers together, and all the variables

(+3/2)a-10=0

We multiply parentheses

3a^2-10=0

a = 3; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·3·(-10)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*3}=\frac{0-2\sqrt{30}}{6}
=-\frac{2\sqrt{30}}{6}
=-\frac{\sqrt{30}}{3}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*3}=\frac{0+2\sqrt{30}}{6}
=\frac{2\sqrt{30}}{6}
=\frac{\sqrt{30}}{3}
$