2(z-3)-(8z-8)=-7z

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Solution for 2(z-3)-(8z-8)=-7z equation: 



2(z-3)-(8z-8)=-7z

We move all terms to the left:

2(z-3)-(8z-8)-(-7z)=0

We multiply parentheses

2z-(8z-8)-(-7z)-6=0

We get rid of parentheses

2z-8z+7z+8-6=0

We add all the numbers together, and all the variables

z+2=0

We move all terms containing z to the left, all other terms to the right

z=-2

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