(3-x)=3(x-4)-12

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Solution for (3-x)=3(x-4)-12 equation: 



(3-x)=3(x-4)-12

We move all terms to the left:

(3-x)-(3(x-4)-12)=0

We add all the numbers together, and all the variables

(-1x+3)-(3(x-4)-12)=0

We get rid of parentheses

-1x-(3(x-4)-12)+3=0



We calculate terms in parentheses: -(3(x-4)-12), so:

3(x-4)-12

We multiply parentheses

3x-12-12

We add all the numbers together, and all the variables

3x-24

Back to the equation:

-(3x-24)



We get rid of parentheses

-1x-3x+24+3=0

We add all the numbers together, and all the variables

-4x+27=0

We move all terms containing x to the left, all other terms to the right

-4x=-27

x=-27/-4

x=6+3/4

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