(3-x)+x+(40-x)+60=500

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Solution for (3-x)+x+(40-x)+60=500 equation: 



(3-x)+x+(40-x)+60=500

We move all terms to the left:

(3-x)+x+(40-x)+60-(500)=0

We add all the numbers together, and all the variables

(-1x+3)+x+(-1x+40)+60-500=0

We add all the numbers together, and all the variables

x+(-1x+3)+(-1x+40)-440=0

We get rid of parentheses

x-1x-1x+3+40-440=0

We add all the numbers together, and all the variables

-1x-397=0

We move all terms containing x to the left, all other terms to the right

-x=397

x=397/-1

x=-397

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