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2x^2-3x-1710=0
a = 2; b = -3; c = -1710;
Δ = b2-4ac
Δ = -32-4·2·(-1710)
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13689}=117$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-117}{2*2}=\frac{-114}{4} =-28+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+117}{2*2}=\frac{120}{4} =30 $
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