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(3-x)(3+3x)=32
We move all terms to the left:
(3-x)(3+3x)-(32)=0
We add all the numbers together, and all the variables
(-1x+3)(3x+3)-32=0
We multiply parentheses ..
(-3x^2-3x+9x+9)-32=0
We get rid of parentheses
-3x^2-3x+9x+9-32=0
We add all the numbers together, and all the variables
-3x^2+6x-23=0
a = -3; b = 6; c = -23;
Δ = b2-4ac
Δ = 62-4·(-3)·(-23)
Δ = -240
Delta is less than zero, so there is no solution for the equation
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