2(2x-2)+2(x+4)=2(x+6)+2(x+2)

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Solution for 2(2x-2)+2(x+4)=2(x+6)+2(x+2) equation: 



2(2x-2)+2(x+4)=2(x+6)+2(x+2)

We move all terms to the left:

2(2x-2)+2(x+4)-(2(x+6)+2(x+2))=0

We multiply parentheses

4x+2x-(2(x+6)+2(x+2))-4+8=0



We calculate terms in parentheses: -(2(x+6)+2(x+2)), so:

2(x+6)+2(x+2)

We multiply parentheses

2x+2x+12+4

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

6x-(4x+16)+4=0

We get rid of parentheses

6x-4x-16+4=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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