(3-5)a-(1/2)a=(9/2)

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Solution for (3-5)a-(1/2)a=(9/2) equation: 



(3-5)a-(1/2)a=(9/2)

We move all terms to the left:

(3-5)a-(1/2)a-((9/2))=0



Domain of the equation: 2)a!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

(-2)a-(+1/2)a-((+9/2))=0

We multiply parentheses

-a^2-2a-((+9/2))=0

We multiply all the terms by the denominator


-a^2*2))-2a*2))-((+9=0

Wy multiply elements

-4a^4=0

We do not support eapression: a^4

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