4(a-3)+4(a-2)=12

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Solution for 4(a-3)+4(a-2)=12 equation: 



4(a-3)+4(a-2)=12

We move all terms to the left:

4(a-3)+4(a-2)-(12)=0

We multiply parentheses

4a+4a-12-8-12=0

We add all the numbers together, and all the variables

8a-32=0

We move all terms containing a to the left, all other terms to the right

8a=32

a=32/8

a=4

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