(3-2x)/4-(5x-2)/6=3+(8x+7)/6

Solution for (3-2x)/4-(5x-2)/6=3+(8x+7)/6 equation:

(3-2x)/4-(5x-2)/6=3+(8x+7)/6

We move all terms to the left:

(3-2x)/4-(5x-2)/6-(3+(8x+7)/6)=0

We add all the numbers together, and all the variables

(-2x+3)/4-(5x-2)/6-(3+(8x+7)/6)=0

We calculate fractions


(-2x)/()+(-20x+8)/()+(-(3+(8x+7)*4)/()=0


We calculate terms in parentheses: +(-(3+(8x+7)*4)/(), so:

-(3+(8x+7)*4)/(

We multiply all the terms by the denominator


-(3+(8x+7)*4)


We calculate terms in parentheses: -(3+(8x+7)*4), so:

3+(8x+7)*4

determiningTheFunctionDomain
(8x+7)*4+3

We multiply parentheses

32x+28+3

We add all the numbers together, and all the variables

32x+31

Back to the equation:

-(32x+31)


We get rid of parentheses

-32x-31

Back to the equation:

+(-32x-31)


We get rid of parentheses

(-2x)/()+(-20x+8)/()-32x-31=0

We multiply all the terms by the denominator


(-2x)+(-20x+8)-32x*()-31*()=0

We add all the numbers together, and all the variables

(-2x)+(-20x+8)-32x*()=0

We get rid of parentheses

-2x-20x-32x*()+8=0

We add all the numbers together, and all the variables

-22x-32x*()+8=0

We move all terms containing x to the left, all other terms to the right

-22x-32x*()=-8