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13-1/4x=3x
We move all terms to the left:
13-1/4x-(3x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-3x-1/4x+13=0
We multiply all the terms by the denominator
-3x*4x+13*4x-1=0
Wy multiply elements
-12x^2+52x-1=0
a = -12; b = 52; c = -1;
Δ = b2-4ac
Δ = 522-4·(-12)·(-1)
Δ = 2656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2656}=\sqrt{16*166}=\sqrt{16}*\sqrt{166}=4\sqrt{166}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-4\sqrt{166}}{2*-12}=\frac{-52-4\sqrt{166}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+4\sqrt{166}}{2*-12}=\frac{-52+4\sqrt{166}}{-24} $
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