(3-2x)+3(1-4x)-4(1-5x)=2(1-3x)

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Solution for (3-2x)+3(1-4x)-4(1-5x)=2(1-3x) equation: 



(3-2x)+3(1-4x)-4(1-5x)=2(1-3x)

We move all terms to the left:

(3-2x)+3(1-4x)-4(1-5x)-(2(1-3x))=0

We add all the numbers together, and all the variables

(-2x+3)+3(-4x+1)-4(-5x+1)-(2(-3x+1))=0

We multiply parentheses

(-2x+3)-12x+20x-(2(-3x+1))+3-4=0

We get rid of parentheses

-2x-12x+20x-(2(-3x+1))+3+3-4=0



We calculate terms in parentheses: -(2(-3x+1)), so:

2(-3x+1)

We multiply parentheses

-6x+2

Back to the equation:

-(-6x+2)



We add all the numbers together, and all the variables

6x-(-6x+2)+2=0

We get rid of parentheses

6x+6x-2+2=0

We add all the numbers together, and all the variables

12x=0

x=0/12

x=0

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