(3-2k)/(k-4)=-3

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Solution for (3-2k)/(k-4)=-3 equation: 



(3-2k)/(k-4)=-3

We move all terms to the left:

(3-2k)/(k-4)-(-3)=0



Domain of the equation: (k-4)!=0

We move all terms containing k to the left, all other terms to the right

k!=4

k∈R



We add all the numbers together, and all the variables

(-2k+3)/(k-4)-(-3)=0

We add all the numbers together, and all the variables

(-2k+3)/(k-4)+3=0

We multiply all the terms by the denominator


(-2k+3)+3*(k-4)=0

We multiply parentheses

(-2k+3)+3k-12=0

We get rid of parentheses

-2k+3k+3-12=0

We add all the numbers together, and all the variables

k-9=0

We move all terms containing k to the left, all other terms to the right

k=9

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