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5(x+2)-2=5(x-5)
We move all terms to the left:
5(x+2)-2-(5(x-5))=0
We multiply parentheses
5x-(5(x-5))+10-2=0
We calculate terms in parentheses: -(5(x-5)), so:We add all the numbers together, and all the variables
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
5x-(5x-25)+8=0
We get rid of parentheses
5x-5x+25+8=0
We add all the numbers together, and all the variables
33!=0
There is no solution for this equation
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