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(3-2i)=(5+4i)
We move all terms to the left:
(3-2i)-((5+4i))=0
We add all the numbers together, and all the variables
(-2i+3)-((4i+5))=0
We get rid of parentheses
-2i-((4i+5))+3=0
We calculate terms in parentheses: -((4i+5)), so:We get rid of parentheses
(4i+5)
We get rid of parentheses
4i+5
Back to the equation:
-(4i+5)
-2i-4i-5+3=0
We add all the numbers together, and all the variables
-6i-2=0
We move all terms containing i to the left, all other terms to the right
-6i=2
i=2/-6
i=-1/3
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