(4+2i)=(-3-5i)

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Solution for (4+2i)=(-3-5i) equation: 



(4+2i)=(-3-5i)

We move all terms to the left:

(4+2i)-((-3-5i))=0

We add all the numbers together, and all the variables

(2i+4)-((-5i-3))=0

We get rid of parentheses

2i-((-5i-3))+4=0



We calculate terms in parentheses: -((-5i-3)), so:

(-5i-3)

We get rid of parentheses

-5i-3

Back to the equation:

-(-5i-3)



We get rid of parentheses

2i+5i+3+4=0

We add all the numbers together, and all the variables

7i+7=0

We move all terms containing i to the left, all other terms to the right

7i=-7

i=-7/7

i=-1

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