(3-2i)(6-4i)=0

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Solution for (3-2i)(6-4i)=0 equation: 



(3-2i)(6-4i)=0

We add all the numbers together, and all the variables

(-2i+3)(-4i+6)=0

We multiply parentheses ..

(+8i^2-12i-12i+18)=0

We get rid of parentheses

8i^2-12i-12i+18=0

We add all the numbers together, and all the variables

8i^2-24i+18=0

a = 8; b = -24; c = +18;
Δ = b2-4ac
Δ = -242-4·8·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{24}{16}=1+1/2$

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