(3+i)*(3-i)=10

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Solution for (3+i)*(3-i)=10 equation: 



(3+i)(3-i)=10

We move all terms to the left:

(3+i)(3-i)-(10)=0

We add all the numbers together, and all the variables

(i+3)(-1i+3)-10=0

We multiply parentheses ..

(-1i^2+3i-3i+9)-10=0

We get rid of parentheses

-1i^2+3i-3i+9-10=0

We add all the numbers together, and all the variables

-1i^2-1=0

a = -1; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-1)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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