(3*6/2)v+10=3*3*3v+9

Solution for (3*6/2)v+10=3*3*3v+9 equation:

(3*6/2)v+10=3*3*3v+9

We move all terms to the left:

(3*6/2)v+10-(3*3*3v+9)=0


Domain of the equation: 2)v!=0

v!=0/1

v!=0

v∈R


We add all the numbers together, and all the variables

(+3*6/2)v-(3*3*3v+9)+10=0

We multiply parentheses

18v^2-(3*3*3v+9)+10=0

We get rid of parentheses

18v^2-3*3*3v-9+10=0

We add all the numbers together, and all the variables

18v^2-3*3*3v+1=0

Wy multiply elements

18v^2-27v*3+1=0

Wy multiply elements

18v^2-81v+1=0

a = 18; b = -81; c = +1;
Δ = b2-4ac
Δ = -812-4·18·1
Δ = 6489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6489}=\sqrt{9*721}=\sqrt{9}*\sqrt{721}=3\sqrt{721}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-3\sqrt{721}}{2*18}=\frac{81-3\sqrt{721}}{36}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+3\sqrt{721}}{2*18}=\frac{81+3\sqrt{721}}{36}
$